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参数资料
| 型号： | MAX15002ATL+ |
| 厂商： | Maxim Integrated Products |
| 文件页数： | 23/29页 |
| 文件大小： | 0K |
| 描述： | IC REG CTRLR BUCK PWM 40-TQFNEP |
| 产品培训模块： | Lead (SnPb) Finish for COTS Obsolescence Mitigation Program |
| 标准包装： | 50 |
| PWM 型： | 电压模式 |
| 输出数： | 2 |
| 频率 - 最大： | 2.2MHz |
| 电源电压： | 5.5 V ~ 23 V |
| 降压： | 是 |
| 升压： | 无 |
| 回扫： | 无 |
| 反相： | 无 |
| 倍增器： | 无 |
| 除法器： | 无 |
| Cuk： | 无 |
| 隔离： | 无 |
| 工作温度： | -40°C ~ 125°C |
| 封装/外壳： | 40-WFQFN 裸露焊盘 |
| 包装： | 管件 |
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MAX15002
Dual-Output Buck Controller with
Tracking/Sequencing
5) The gain of the modulator (Gain MOD )—comprised
of the regulator’s pulse-width modulator, LC filter,
feedback divider, and associated circuitry —at
crossover frequency is:
If a ceramic capacitor is used, the capacitor ESR
zero, f ESR , is likely to be located even above one-
half of the switching frequency, that is f LC < f CO <
f SW /2 < f ESR . In this case, the frequency of the sec-
ond pole (f P2 ) should be placed high enough not to
Gain MOD = 4 ×
1
( 2 π × f CO ) 2 × L × C OUT
significantly erode the phase margin at the
crossover frequency. For example, it can be set at 5
x f CO , so that its contribution to phase loss at the
The gain of the error amplifier (Gain E/A ) in midband fre-
quencies is:
Gain E/A = 2 π x f CO x C I x R F
crossover frequency f CO is only about 11°:
f P2 = 5 x f CO
Once f P2 is known, calculate R I :
The total loop gain as the product of the modulator gain
and the error-amplifier gain at f CO should be equal to 1,
as follows:
R I =
1
2 π × f P 2 × C I
So :
Gain MOD × Gain E A = 1
7) Place the second zero (f Z2 ) at 0.2 x f CO or at f LC ,
whichever is lower and calculate R 1 using the fol-
lowing equation:
( 2 π × f CO OUT × L
) × C
4 ×
2
1
× 2 π × f CO × C I × R F = 1
R 1 =
1
2 π × f Z 2 × C I
? R I
( 2 π × f CO × L × C OUT )
4 × R F
C CF =
Solving fo r C I :
C I =
6) For those situations where f LC < f CO < f ESR <
f SW /2—as with low-ESR tantalum capacitors—the
compensator’s second pole (f P2 ) should be used to
cancel f ESR . This provides additional phase margin.
8) Place the third pole (f P3 ) at 1/2 the switching fre-
quency and calculate C CF from:
1
2 π × 0 . 5 × f SW × R F
9) Calculate R 2 as:
Viewed mathematically on the system Bode plot, the
loop gain plot maintains its +20dB/dec slope up to
1/2 of the switching frequency verses flattening out
soon after the 0dB crossover. Then set:
f P2 = f ESR
Maxim Integrated
R 2 = R 1 ×
where V FB = 0.6V.
V FB
V OUT ? V FB
23
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相关代理商/技术参数 |
参数描述 |
|---|---|
| MAX15002ATL+ | 功能描述:DC/DC 开关控制器 Dual-Out Buck Ctlr w/Track/Sequence RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
| MAX15002ATL+T | 功能描述:DC/DC 开关控制器 Dual-Out Buck Ctlr w/Track/Sequence RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
| MAX15003ATM+ | 功能描述:DC/DC 开关控制器 Triple-Out Buck Ctlr w/Track/Sequence RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
| MAX15003ATM+T | 功能描述:DC/DC 开关控制器 Triple-Out Buck Ctlr w/Track/Sequence RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
| MAX15003EVKIT+ | 功能描述:电源管理IC开发工具 MAX15003 Eval Kit RoHS:否 制造商:Maxim Integrated 产品:Evaluation Kits 类型:Battery Management 工具用于评估:MAX17710GB 输入电压: 输出电压:1.8 V |
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